day 3 in the books
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03/input
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03/input
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146
03/main.go
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146
03/main.go
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package main
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import (
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"bufio"
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"fmt"
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"os"
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"strings"
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)
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func main() {
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partOne()
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partTwo()
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}
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type slope struct {
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rise int
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run int
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trees int
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position int
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}
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type terrain struct {
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row []string
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}
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func (t terrain) isTree(poss int) bool {
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return t.row[poss%len(t.row)] == "#"
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}
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// You start on the open square (.) in the top-left corner and need to reach the bottom (below the bottom-most row on your map).
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// The toboggan can only follow a few specific slopes (you opted for a cheaper model that prefers rational numbers);
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// start by counting all the trees you would encounter for the slope right 3, down 1:
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// From your starting position at the top-left, check the position that is right 3 and down 1.
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// Then, check the position that is right 3 and down 1 from there, and so on until you go past the bottom of the map.
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// The locations you'd check in the above example are marked here with O where there was an open square and X where there was a tree:
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// ..##.........##.........##.........##.........##.........##....... --->
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// #..O#...#..#...#...#..#...#...#..#...#...#..#...#...#..#...#...#..
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// .#....X..#..#....#..#..#....#..#..#....#..#..#....#..#..#....#..#.
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// ..#.#...#O#..#.#...#.#..#.#...#.#..#.#...#.#..#.#...#.#..#.#...#.#
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// .#...##..#..X...##..#..#...##..#..#...##..#..#...##..#..#...##..#.
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// ..#.##.......#.X#.......#.##.......#.##.......#.##.......#.##..... --->
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// .#.#.#....#.#.#.#.O..#.#.#.#....#.#.#.#....#.#.#.#....#.#.#.#....#
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// .#........#.#........X.#........#.#........#.#........#.#........#
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// #.##...#...#.##...#...#.X#...#...#.##...#...#.##...#...#.##...#...
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// #...##....##...##....##...#X....##...##....##...##....##...##....#
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// .#..#...#.#.#..#...#.#.#..#...X.#.#..#...#.#.#..#...#.#.#..#...#.# --->
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// In this example, traversing the map using this slope would cause you to encounter 7 trees.
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// Starting at the top-left corner of your map and following a slope of right 3 and down 1, how many trees would you encounter?
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func partOne() {
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f, _ := os.Open("input")
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reader := bufio.NewReader(f)
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scanner := bufio.NewScanner(reader)
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depth := 0
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s := slope{
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rise: 1,
|
||||
run: 3,
|
||||
trees: 0,
|
||||
position: 0,
|
||||
}
|
||||
|
||||
for scanner.Scan() {
|
||||
e := terrain{
|
||||
row: strings.Split(scanner.Text(), ""),
|
||||
}
|
||||
if depth%s.rise == 0 && e.isTree(s.position) {
|
||||
s.trees = s.trees + 1
|
||||
}
|
||||
s.position = s.position + s.run
|
||||
depth = depth + s.rise
|
||||
}
|
||||
|
||||
fmt.Println(s.trees)
|
||||
}
|
||||
|
||||
// Determine the number of trees you would encounter if, for each of the following slopes, you start at the top-left corner and traverse the map all the way to the bottom:
|
||||
// Right 1, down 1.
|
||||
// Right 3, down 1. (This is the slope you already checked.)
|
||||
// Right 5, down 1.
|
||||
// Right 7, down 1.
|
||||
// Right 1, down 2.
|
||||
// In the above example, these slopes would find 2, 7, 3, 4, and 2 tree(s) respectively; multiplied together, these produce the answer 336.
|
||||
|
||||
func partTwo() {
|
||||
f, _ := os.Open("input")
|
||||
reader := bufio.NewReader(f)
|
||||
scanner := bufio.NewScanner(reader)
|
||||
|
||||
slopes := []*slope{
|
||||
{
|
||||
rise: 1,
|
||||
run: 1,
|
||||
trees: 0,
|
||||
position: 0,
|
||||
},
|
||||
{
|
||||
rise: 1,
|
||||
run: 3,
|
||||
trees: 0,
|
||||
position: 0,
|
||||
},
|
||||
{
|
||||
rise: 1,
|
||||
run: 5,
|
||||
trees: 0,
|
||||
position: 0,
|
||||
},
|
||||
{
|
||||
rise: 1,
|
||||
run: 7,
|
||||
trees: 0,
|
||||
position: 0,
|
||||
},
|
||||
{
|
||||
rise: 2,
|
||||
run: 1,
|
||||
trees: 0,
|
||||
position: 0,
|
||||
},
|
||||
}
|
||||
|
||||
depth := 0
|
||||
|
||||
for scanner.Scan() {
|
||||
e := terrain{
|
||||
row: strings.Split(scanner.Text(), ""),
|
||||
}
|
||||
for _, s := range slopes {
|
||||
if depth%s.rise == 0 {
|
||||
// check tree
|
||||
if e.isTree(s.position) {
|
||||
s.trees = s.trees + 1
|
||||
}
|
||||
// only increment position if we're "on" for this row; handles the rise > run case
|
||||
s.position = s.position + s.run
|
||||
}
|
||||
// always move on a row
|
||||
depth = depth + 1
|
||||
}
|
||||
}
|
||||
|
||||
// can't be bothered to write out the loop
|
||||
fmt.Println(slopes[0].trees * slopes[1].trees * slopes[2].trees * slopes[3].trees * slopes[4].trees)
|
||||
}
|
||||
Loading…
Reference in New Issue
Block a user