give up and do part 2 via a for loop
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@@ -18,9 +18,9 @@ public class Day00 {
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sb.append("\n");
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}
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String input = sb.toString();
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System.out.println(input);
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IO.println(input);
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} catch (Exception e) {
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System.out.println(e.getMessage());
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IO.println(e.getMessage());
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}
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}
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@@ -33,9 +33,9 @@ public class Day00 {
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sb.append("\n");
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}
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String input = sb.toString();
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System.out.println(input);
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IO.println(input);
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} catch (Exception e) {
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System.out.println(e.getMessage());
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IO.println(e.getMessage());
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}
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}
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}
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@@ -6,7 +6,7 @@ import java.util.Scanner;
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public class Day02 {
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public static void main(String[] args) {
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part1();
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// part2();
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part2();
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}
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private static void part1() {
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@@ -26,24 +26,31 @@ public class Day02 {
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start = permute(start);
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}
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}
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System.out.println(sum);
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IO.println(sum);
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} catch (Exception e) {
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System.out.println(e.getMessage());
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IO.println(e.getMessage());
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}
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}
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// fine, we'll just iterate the whole range
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// can probably do this by bitshifting instead of long<->string conversions
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private static void part2() {
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try (Scanner scanner = new Scanner(new FileReader("resources/inputs/02/input"))) {
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StringBuilder sb = new StringBuilder();
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while (scanner.hasNextLine()) {
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sb.append(scanner.nextLine());
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sb.append("\n");
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try (Scanner scanner = new Scanner(new FileReader("resources/inputs/02/input")).useDelimiter(",")) {
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long sum = 0L;
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while (scanner.hasNext()) {
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String input = scanner.next().trim();
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String[] range = input.split("-");
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long start = Long.parseLong(range[0]);
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long end = Long.parseLong(range[1]);
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for (long i = start; i <= end; i++) {
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if (hasPattern(String.valueOf(i))) {
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sum += i;
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}
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}
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}
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String input = sb.toString();
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System.out.println(input);
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IO.println(sum);
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} catch (Exception e) {
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System.out.println(e.getMessage());
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IO.println(e.getMessage());
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}
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}
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@@ -52,23 +59,32 @@ public class Day02 {
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// odd length, can't have a repeated pair
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return false;
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}
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return CharSequence.compare(
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id.subSequence(0, id.length() / 2),
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id.subSequence(id.length() / 2, id.length())) == 0;
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return id.substring(0, id.length() / 2) == id.substring(id.length() / 2);
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}
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private static String permute(String str) {
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if (str.length() % 2 != 0) {
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// in this case, we need to get to a even-length string
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return String.valueOf((int) Math.pow(10, str.length() / 2))
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+ String.valueOf((int) Math.pow(10, str.length() / 2));
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return String.valueOf((long) Math.pow(10, str.length() / 2))
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+ String.valueOf((long) Math.pow(10, str.length() / 2));
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}
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long head = Long.parseLong(str.subSequence(0, str.length() / 2).toString());
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long tail = Long.parseLong(str.subSequence(str.length() / 2, str.length()).toString());
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long head = Long.parseLong(str.substring(0, str.length() / 2));
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long tail = Long.parseLong(str.substring(str.length() / 2, str.length()));
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if (tail < head) {
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return String.valueOf(head) + String.valueOf(head);
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}
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head++;
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return String.valueOf(head) + String.valueOf(head);
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}
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// don't need regexes, at least
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private static boolean hasPattern(String str) {
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for (int patternLength = 1; patternLength <= str.length() / 2; patternLength++) {
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String candidate = str.substring(0, patternLength).repeat(str.length() / patternLength);
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if (candidate.equals(str)) {
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return true;
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}
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}
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return false;
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}
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}
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